<\/div>\n
\nThe Bee World<\/em> \u2013 June, 1944 \u2013 Page 46
\nMISCELLANY<\/strong>
\nGeometry of the Ideal Bee\u2019s Cell<\/em>. The bee\u2019s cell was the object of much discussion by amateur mathematicians (and some who were more eminent) in the 18th and 19th centuries. A good deal of nonsense was written on the subject, for many of the writers did not realise how seldom bees build cells conforming to the ideal pattern, nor that the resulting cell-form depends much more upon the stresses in the semi-plastic wax inside the warm building-cluster than upon such considerations as an instinct for using the least amount of wax possible. See B.W. 3, 37<\/em>, for the history of the problem.
\n![\"\"](\"http:\/\/www.resistantbees.com\/fotos\/blog\/lusby-geometry-ideal-cell-1.gif\")
\nNone of the investigators seem, however, to have hit upon the interesting approximate solution of the problem of \u201csquaring the circle\u201d provided by the so-seldom-realised ideal cell. ABCD is one of the rhombs or lozenges from the base of such a cell, AC and BD its diagonals, meeting at O. Bisect the angle ABO by line BE. With BE as radius and centre B, describe a circle, cutting AC at E. The square on BD (or 2 x BO) is nearly equal to the area of this circle.<\/em> The proof is easy, recalling that BO, OA and AB are in the proportions of the square roots of 1, 2 and 3 to one another; while OB\/BA, being the cosine of the angle ABO (or 2 x angle EBO) is, by a well-known rule, equal to 2(OB\/EB)2-1.
\nNow (2.OB\/BE)2=(area of square PQRS divided by square of radius BE)=\u201dpi,\u201d nearly. This, from the above, is = 2(OB\/BA+1) = 2(1\/3 of the square root of 3+1)=2\u00d71.57735=3.1547.
\nThis is not a very close approximation, to \u201cpi,\u201d being about 4% out. But it is closer than the Egyptians\u2019 value, the square of 16\/9, or 3.1605. The accurate value, to 4 places of decimals, is 3.1416; and the usual rough approximation 22\/7, is about 0.4% out.
\nA.D.B.\n<\/div>\n","protected":false},"excerpt":{"rendered":"Geometry of the Ideal Bee\u2019s Cell - ResistantBees_english<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/english.resistantbees.es\/?p=983\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Geometry of the Ideal Bee\u2019s Cell - ResistantBees_english\" \/>\n<meta property=\"og:description\" content=\"Geometry of the Ideal Bee\u2019s Cell Geometry of the Ideal Bee\u2019s Cell The Bee World \u2013 June, 1944 \u2013 Page 46 MISCELLANY Geometry of the Ideal Bee\u2019s Cell. 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\nMISCELLANY<\/strong>
\nGeometry of the Ideal Bee\u2019s Cell<\/em>. The bee\u2019s cell was the object of much discussion by amateur mathematicians (and some who were more eminent) in the 18th and 19th centuries. A good deal of nonsense was written on the subject, for many of the writers did not realise how seldom bees build cells conforming to the ideal pattern, nor that the resulting cell-form depends much more upon the stresses in the semi-plastic wax inside the warm building-cluster than upon such considerations as an instinct for using the least amount of wax possible. See B.W. 3, 37<\/em>, for the history of the problem.
\n
\nNone of the investigators seem, however, to have hit upon the interesting approximate solution of the problem of \u201csquaring the circle\u201d provided by the so-seldom-realised ideal cell. ABCD is one of the rhombs or lozenges from the base of such a cell, AC and BD its diagonals, meeting at O. Bisect the angle ABO by line BE. With BE as radius and centre B, describe a circle, cutting AC at E. The square on BD (or 2 x BO) is nearly equal to the area of this circle.<\/em> The proof is easy, recalling that BO, OA and AB are in the proportions of the square roots of 1, 2 and 3 to one another; while OB\/BA, being the cosine of the angle ABO (or 2 x angle EBO) is, by a well-known rule, equal to 2(OB\/EB)2-1.
\nNow (2.OB\/BE)2=(area of square PQRS divided by square of radius BE)=\u201dpi,\u201d nearly. This, from the above, is = 2(OB\/BA+1) = 2(1\/3 of the square root of 3+1)=2\u00d71.57735=3.1547.
\nThis is not a very close approximation, to \u201cpi,\u201d being about 4% out. But it is closer than the Egyptians\u2019 value, the square of 16\/9, or 3.1605. The accurate value, to 4 places of decimals, is 3.1416; and the usual rough approximation 22\/7, is about 0.4% out.
\nA.D.B.\n<\/div>\n","protected":false},"excerpt":{"rendered":"
Geometry of the Ideal Bee\u2019s Cell Geometry of the Ideal Bee\u2019s Cell The Bee World \u2013 June, 1944 \u2013 Page 46 MISCELLANY Geometry of the Ideal Bee\u2019s Cell. The bee\u2019s…<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":[],"categories":[89],"tags":[],"yoast_head":"\n